49x^2-28x-12=0

Solution for 49x^2-28x-12=0 equation:

49x^2-28x-12=0

a = 49; b = -28; c = -12;
Δ = b2-4ac
Δ = -282-4·49·(-12)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-56}{2*49}=\frac{-28}{98}
=-2/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+56}{2*49}=\frac{84}{98}
=6/7
$